charAt5 [백준] 2675번: 문자열 반복 - java 풀이 import java.io.BufferedReader; import java.io.IOException; import java.io.InputStreamReader; import java.util.StringTokenizer; public class Main { public static void main(String[] args) throws IOException{ BufferedReader br = new BufferedReader(new InputStreamReader(System.in)); int T = Integer.parseInt(br.readLine()); StringBuilder sb = new StringBuilder(); for(int i=0; i 2023. 6. 19. [백준] 9086번: 문자열 - java 풀이 getBytes() 이용한 풀이 import java.io.BufferedReader; import java.io.IOException; import java.io.InputStreamReader; public class Main { public static void main(String[] args) throws IOException{ BufferedReader br = new BufferedReader(new InputStreamReader(System.in)); int T = Integer.parseInt(br.readLine()); StringBuilder sb = new StringBuilder(); for(int i=0; i 2023. 6. 19. [백준] 11720번: 숫자의 합 - java 풀이 charAt()을 이용한 풀이 import java.io.BufferedReader; import java.io.IOException; import java.io.InputStreamReader; public class Main { public static void main(String[] args) throws IOException{ BufferedReader br = new BufferedReader(new InputStreamReader(System.in)); int N = Integer.parseInt(br.readLine()); String str = br.readLine(); br.close(); int sum=0; for(int i=0; i 2023. 6. 18. [백준]10952:A+B - 5 - java풀이 간단하게 풀 수 있는 문제다. BufferedReader+charAt+BufferedWriter import java.io.BufferedReader; import java.io.BufferedWriter; import java.io.IOException; import java.io.InputStreamReader; import java.io.OutputStreamWriter; public class Main { public static void main(String[] args) throws IOException { BufferedReader br = new BufferedReader(new InputStreamReader(System.in)); BufferedWriter bw = new Buffere.. 2023. 4. 4. [백준]2588번: 곱셈 - java 풀이 문자 타입으로 입력 받은 숫자를 어떻게 쪼개어 사용할지가 핵심인 문제다. charAt() 풀이 import java.io.BufferedReader; import java.io.IOException; import java.io.InputStreamReader; public class Main { public static void main(String[] args) throws IOException { BufferedReader br = new BufferedReader(new InputStreamReader(System.in)); int A = Integer.parseInt(br.readLine()); String Bstr = br.readLine(); int B = Integer.parseInt(Bst.. 2023. 3. 25. 이전 1 다음